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Exercise 5

Write some code to create a deep copy of the dict1 object and assign it to dict2. You should only modify the code where indicated.

# You may modify this line

dict1 = {
    'a': [[7, 1], ['aa', 'aaa']],
    'b': ([3, 2], ['bb', 'bbb']),
}

dict2 = ??? # You may modify the `???` part
            # of this line

# All of these should print False
print(dict1         is dict2)
print(dict1['a']    is dict2['a'])
print(dict1['a'][0] is dict2['a'][0])
print(dict1['a'][1] is dict2['a'][1])
print(dict1['b']    is dict2['b'])
print(dict1['b'][0] is dict2['b'][0])
print(dict1['b'][1] is dict2['b'][1])

Solution

# highlight
import copy
# endhighlight

dict1 = {
    'a': [[7, 1], ['aa', 'aaa']],
    'b': ([3, 2], ['bb', 'bbb']),
}

# highlight
dict2 = copy.deepcopy(dict1)
# endhighlight

Deep copies create entirely new objects, including their nested contents. We can use copy.deepcopy to create a deep copy.

Note that we don't check the immutable contents of the nested objects inside each list value in the dictionaries. Since they are all immutable, they weren't duplicated. Try it by adding these additional tests.

# All of these should print True

print(dict1['a'][0][0] is dict2['a'][0][0])
print(dict1['a'][0][1] is dict2['a'][0][1])
print(dict1['a'][1][0] is dict2['a'][1][0])
print(dict1['a'][1][1] is dict2['a'][1][1])
print(dict1['b'][0][0] is dict2['b'][0][0])
print(dict1['b'][0][1] is dict2['b'][0][1])
print(dict1['b'][1][0] is dict2['b'][1][0])
print(dict1['b'][1][1] is dict2['b'][1][1])

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