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Exercise 3

Without running this code, what will it print? Why?

dict1 = {
    "Hitchhiker's Guide to the Galaxy": 42,
    'Monty Python': 'The Life of Brian',
    'Airplane!': "Don't call me Shirley!",
}

dict2 = dict(dict1)
dict2['Monty Python'] = 'Holy Grail'
print(dict1['Monty Python'])

Solution

The code outputs:

The Life of Brian

The constructor call dict(dict1) creates a new dict that contains the same key/value pairs as dict1. Thus, dict2 is not the same object as dict1. When we change the value associated with the 'Monty Python' key in dict2, we don't see a corresponding change in dict1.

This code demonstrates that two identical objects aren't necessarily the same object. If you assign an object associated with variable a to variable b, the variables share that object. However, if the value assigned to b is an entirely new object, there is no sharing, even if the values are identical.

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