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Exercise 6

What will the following code print?

print('abc-def'.isalpha())
print('abc_def'.isalpha())
print('abc def'.isalpha())
print('abc def'.isalpha() and
      'abc def'.isspace())
print('abc def'.isalpha() or
      'abc def'.isspace())
print('abcdef'.isalpha())
print('31415'.isdigit())
print('-31415'.isdigit())
print('31_415'.isdigit())
print('3.1415'.isdigit())
print(''.isspace())

Solution

print('abc-def'.isalpha())       # False
print('abc_def'.isalpha())       # False
print('abc def'.isalpha())       # False
print('abc def'.isalpha() and
      'abc def'.isspace())       # False
print('abc def'.isalpha() or
      'abc def'.isspace())       # False
print('abcdef'.isalpha())        # True
print('31415'.isdigit())         # True
print('-31415'.isdigit())        # False
print('31_415'.isdigit())        # False
print('3.1415'.isdigit())        # False
print(''.isspace())              # False

There are two things to note above.

  • Lines 4-7: You can't use and or or to determine whether a string contains a mixture of different value types. The str.isXXXXX methods determine whether every character in strmatches a certain class of characters. Thus, a string can't be both alphabetic and whitespace. It can be alphabetic or whitespace, but that doesn't work for something like 'abc def'.
  • Line 13: Most of the str.isXXXXX methods return False when invoked by an empty string.

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