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Exercise 8

This problem is more challenging than most in this book. Don't worry if you can't solve it on your own.

Write a function similar to the oddLengths function from Exercise 6, but don't use map or filter. Instead, try to use the reduce method.

let arr = ['a', 'abcd', 'abcde', 'abc', 'ab'];
console.log(oddLengths(arr)); // => [1, 5, 3]

Use an array as the accumulator. Ideally, you should be able to use the return value of reduce as the return value of the function.

Solution

function oddLengths(strings) {
  return strings.reduce((filteredNumbersArray, letters) => {
    let length = letters.length;
    if (length % 2 === 1) {
      filteredNumbersArray.push(length);
    }

    return filteredNumbersArray;
  }, []);
}

let arr = ['a', 'abcd', 'abcde', 'abc', 'ab'];
console.log(oddLengths(arr));

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