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Exercise 2

Implement a solution that performs a level-order traversal of a binary tree.

Solution

function bfs(root) {
  const result = [];
  if (root === null) {
      return result;
  }

  const queue = [root];

  while (queue.length > 0) {
    const node = queue.shift();
    result.push(node.val);

    if (node.left !== null) {
      queue.push(node.left);
    }
    if (node.right !== null) {
      queue.push(node.right);
    }
  }

  return result;
}

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