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Exercise 2

Implement a breadth-first search (BFS) on the same graph using a queue and a visited set. Traverse the graph starting from a given source node and print the nodes in BFS order.

// Implement a function `bfs` that accepts two arguments: the adjacency list
// representing an undirected graph and a starting vertex (source).
// The function should print the vertices in breadth-first
// traversal order.

function bfs(adjList, source) {
  // implementation goes here
}

const adjList = new Map();
adjList.set(1, [2, 3]);
adjList.set(2, [1, 4]);
adjList.set(3, [1, 4, 5]);
adjList.set(4, [2, 3]);
adjList.set(5, [3, 6]);
adjList.set(6, [5]);

console.log(bfs(adjList, 1)); // 1, 2, 3, 4, 5, 6 or 1, 3, 2, 5, 4, 6

Solution

function bfs(adjList, source) {
  let queue = [source];
  let visited = new Set([source]);

  while (queue.length !== 0) {
    let current = queue.shift();
    console.log(current);

    let neighbors = adjList.get(current);
    for (let neighbor of neighbors) {
      if (!visited.has(neighbor)) {
        visited.add(neighbor);
        queue.push(neighbor);
      }
    }
  }
}

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